使用不同的估计器测量周长

在本示例中，我们展示了测量周长的误差，比较了经典近似值和 Crofton 近似值。为此，我们估计了一个物体（正方形或圆盘）及其旋转版本，并随着我们增加旋转角度，对其进行估计。

import matplotlib.pyplot as plt
import numpy as np

from skimage.measure import perimeter, perimeter_crofton
from skimage.transform import rotate


# scale parameter can be used to increase the grid size. The resulting curves
# should be smoothed with higher scales
scale = 10

# Construct two objects, a square and a disk
square = np.zeros((100 * scale, 100 * scale))
square[40 * scale : 60 * scale, 40 * scale : 60 * scale] = 1

[X, Y] = np.meshgrid(np.linspace(0, 100 * scale), np.linspace(0, 100 * scale))
R = 20 * scale
disk = (X - 50 * scale) ** 2 + (Y - 50 * scale) ** 2 <= R**2

fig, axes = plt.subplots(1, 2, figsize=(8, 5))
ax = axes.flatten()

dX = X[0, 1] - X[0, 0]
true_perimeters = [80 * scale, 2 * np.pi * R / dX]

# For each type of object, estimate its perimeter as the object is rotated,
# according to different approximations
for index, obj in enumerate([square, disk]):
    # `neighborhood` value can be 4 or 8 for the classic perimeter estimator
    for n in [4, 8]:
        p = []
        angles = range(90)
        for i in angles:
            rotated = rotate(obj, i, order=0)
            p.append(perimeter(rotated, n))
        ax[index].plot(angles, p)

    # `directions` value can be 2 or 4 for the Crofton estimator
    for d in [2, 4]:
        p = []
        angles = np.arange(0, 90, 2)
        for i in angles:
            rotated = rotate(obj, i, order=0)
            p.append(perimeter_crofton(rotated, d))
        ax[index].plot(angles, p)

    ax[index].axhline(true_perimeters[index], linestyle='--', color='k')
    ax[index].set_xlabel('Rotation angle')
    ax[index].legend(
        [
            'N4 perimeter',
            'N8 perimeter',
            'Crofton 2 directions',
            'Crofton 4 directions',
            'Ground truth',
        ],
        loc='best',
    )
    ax[index].set_ylabel('Perimeter of the rotated object')

ax[0].set_title('Square')
ax[1].set_title('Disk')
plt.tight_layout()
plt.show()